q^2+27=11

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Solution for q^2+27=11 equation: 



q^2+27=11

We move all terms to the left:

q^2+27-(11)=0

We add all the numbers together, and all the variables

q^2+16=0

a = 1; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·1·16
Δ = -64
Delta is less than zero, so there is no solution for the equation

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